Add android ui

terminal_ui.py

@@ -0,0 +1,43 @@
+def query(text):
+    return input(f"{text} \n> ")
+
+
+def query_int(text):
+    try:
+        ans = query(text)
+        return int(ans)
+    except ValueError:
+        print("Please enter a valid number!")
+        return query_int(text)
+
+
+def query_yes_no(question, default="no"):
+    """Ask a yes/no question via raw_input() and return their answer.
+
+    https://stackoverflow.com/questions/3041986/apt-command-line-interface-like-yes-no-input
+
+    "question" is a string that is presented to the user.
+    "default" is the presumed answer if the user just hits <Enter>.
+            It must be "yes" (the default), "no" or None (meaning
+            an answer is required of the user).
+
+    The "answer" return value is True for "yes" or False for "no".
+    """
+    valid = {"yes": True, "y": True, "ye": True, "no": False, "n": False}
+    if default is None:
+        prompt = " [y/n] "
+    elif default == "yes":
+        prompt = " [Y/n] "
+    elif default == "no":
+        prompt = " [y/N] "
+    else:
+        raise ValueError("invalid default answer: '%s'" % default)
+
+    while True:
+        choice = query(question + prompt).lower()
+        if default is not None and choice == "":
+            return valid[default]
+        elif choice in valid:
+            return valid[choice]
+        else:
+            print("Please respond with 'yes' or 'no' (or 'y' or 'n').")